X(x+4)=140^2

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Solution for X(x+4)=140^2 equation:



X(X+4)=140^2
We move all terms to the left:
X(X+4)-(140^2)=0
We add all the numbers together, and all the variables
X(X+4)-19600=0
We multiply parentheses
X^2+4X-19600=0
a = 1; b = 4; c = -19600;
Δ = b2-4ac
Δ = 42-4·1·(-19600)
Δ = 78416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{78416}=\sqrt{2704*29}=\sqrt{2704}*\sqrt{29}=52\sqrt{29}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-52\sqrt{29}}{2*1}=\frac{-4-52\sqrt{29}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+52\sqrt{29}}{2*1}=\frac{-4+52\sqrt{29}}{2} $

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